Get The Path Of A File Using OpenFileDialog In C#

This snippet uses the OpenFileDialog class to get a files path.

1. OpenFileDialog FD = new OpenFileDialog();
3. string filenname = "";
4. string path = "";
6. if (FD.ShowDialog() == DialogResult.OK)
7. {
8.   filenname = System.IO.Path.GetFileName(FD.FileName);
9.   path = System.IO.Path.GetDirectoryName(FD.FileName);
10. }
12. MessageBox.Show(filenname, "Filename");
13. MessageBox.Show(path, "Directory");